Originally posted by: rajnish_here
oops i thought this que is part of game and answered. but this is for jasleen. so editedππ
Originally posted by: bhopalyellow
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ans. : as u explained that the min. force which can stop the book from sliding is the required force , so the min. force here is 2N , although the book is pushed with 3N but the min. force is 2N which is enough to stop the book from sliding , so the ans. is 2 N .Your final answer that the force of static friction =2N is correct. But the reasoning has some fallacy. Let me explain the correct reasoning.Suppose that I apply force towards right.Coeff. of static friction us = 0.2Normal force Fn = 10 NTherefore maximum value of static friction = 0.2 * 10 N = 2 NI apply 3 N force towards right. This means that 3 N friction towards left is needed to stop the book from moving.But static friction can be at maximum 2 N. It cannot be more than this.So static friction = 2 N.I apply 3 N towards right and friction is 2 N towards left. This means that friction will not be able to balance my force and the book will move towards right.What will happen after that? The answer is that once the book starts moving, then kinetic friction takes over.So, for a very short time, there is static friction of 2 N. Then the book starts moving and after that there is kinetic friction.Note that us*Fn is the maximum static friction. If less than this is enough to stop the book from sliding, then static friction will be less. But static friction can never become more than us*Fn. If more friction is needed to stop the book from moving, then the book WILL MOVE and static friction will be us*Fn.Let me know if you need further clarification.
Originally posted by: bhopalyellow
am i right brother.....i don't think so.....plz tellF=m*aa=f/m=2/10 2=0.2 m/(sec) π
Originally posted by: bhopalyellow
[quote=akhl]Jaslees,
I edited my explanation and in the end, have added a question. It is only for your learning. Can you tackle that? And also please try answering the following question. This is also not a part of the game but only as learning exercise.A book is kept on the table. Both are moving towards north. Table is moving at 2 m/s and book is moving at 1 m/s. Both these values are relative to ground.What is the direction of force of friction on the book?[/quote]i think.......the relative speed=speed (moving table - book)
=2-1 = 1 m/sec.and as the friction opposes the force on the book and the force is in north direction so the friction will be in opp. i.e., south direction........π
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