chemical sleuthing HELP!

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Posted: 13 years ago
please click on the links below to help me out..


http://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-ash1/168646_196916983667820_100000485604492_732943_6260058_n.jpg

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Edited by happy07 - 13 years ago
Posted: 13 years ago
Answers to
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A forms bubbles, bubbles/blue and bubbles. Therefore A is baking powder.
A forms bubbles/blue with Y. Therefore Y is iodine.
B forms bubbles with one liquid and has NR with other liquids. Therefore, B is baking soda.
B forms bubbles with X. Therefore X is vinegar.
Therefore the remaining liquid Z is water.
C has NR with all the three liquids. Therefore, C is table salt.
D has NR with two liquids and blue color with one. Therefore, D is starch.

Ans:
A  Baking Powder
B Baking Soda
C Table Salt
D Starch

X Vinegar
Y Iodine
Z Water

Posted: 13 years ago

Answers of
http://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-ash1/167579_196916613667857_100000485604492_732940_6848009_n.jpg

1 and 3 form gas bubbles. Therefore, between them one is HCl and the other is Na2CO3.
Between HCl and Na2CO3, it is Na2CO3 which gives NH3 odor. Between 1 and 3, it is 1 which gives NH3 odor.
Therefore 1 = Na2CO3
and 3 = HCl

Na2CO3 gives NH3 order with (NH4)2SO4 and 1 gives NH3 odor with 4
Therefore 4 = (NH4)2SO4

The remaining from first table is BaCl2 and from second table is 2.
Therefore 2 = BaCl2

1 Na2CO3
2 BaCl2
3 HCl
4 (NH4)2SO4

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